Scenario From Oracle Forum

This function seems like a good idea for password validation, for example one number and 4-8 characters.

However, this does not work - any ideas?

select
1 from dual where
regexp_like(upper(’PA55WORD’),’^(?=.*\d).{4,8}$’)

Solution which I gave:

WITH data_Set AS
(
SELECT 1 row_no, ‘3434HERE’ text_col FROM dual
UNION ALL
SELECT 2 row_no, ‘EYRERY787′ text_col FROM dual
UNION ALL
SELECT 3 row_no, ‘DHFD67SDSD’ text_col FROM dual
UNION ALL
SELECT 4 row_no, ‘ERERT’ text_col FROM dual
UNION ALL
SELECT 4 row_no, ‘23232′ text_col FROM dual
)
SELECT row_no FROM data_set
WHERE REGEXP_LIKE(UPPER(text_col),’([[:alpha:]]+[[:digit:]]+[[:alpha:]]+)|([[:digit:]]+[[:alpha:]]+)|([[:alpha:]]+[[:digit:]]+)’)
/

Result as follows:
ROW_NO
———-
1
2
3